数列{an}满足a1=1,a2=2,an+2=[1+cos(nπ/2)]an+sin(nπ/2),n=1,2,3… (1)求a3,a4,并求数列{an}的通项公式 (2)设bn=a2n-1/a2n,Sn=b1+b2+…+bn 证明:当n≥6时,丨Sn-2丨<1/n
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