求极限,难难难,急如何求极限:(x→0)lim[(1+tanx)/(1+sinx)]^(1/x^3) 1.先取对数.2.利用洛必达法则,可以得到lim cosx*(1+sinx)/(cosx+sinx)*d((cosx+sinx)/(cosx*(1+sinx)))/dx/(3*x^2)3.进一步化简为lim (1-(cosx)^3+(sinx)^3)/(3*
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/13 01:38:19
xV[OW+m^v] R#K!RЇJn[vآ-K/(vή9bдҗJ~3|3sֳsx[lzg><^dbKsȭ%?ג_n?tu}i-iiGHSB͎ZmR0X/>ne6ĉGMJM|zUʷ8qђY%rukiNMۺc~;#R }ZrRFi'0Aw[7/m|ِcJȩa'-Z^Q !@r2aN# )pbkYBOrW_E ?.jyݠ=7B^/7Q.\n{Jګ.NAlTʼng NףwQ(=*x~Ѩ"vܠy6oB
zqaCmtEb
@OZ:Cbiu3,MSq._E12\s8aiYw[uO"5T(~䧧B2$oSjL`4DZ#
,0|~EɁ;V7D- }s%L5CQ
+1mO^XBU﵊76=mH *AD=k6&,Ky'tvXw1I|ePeꇬ
@r(\~jnU47;>OLV f+h8&Q_~!'6pu8K?2b'yWxB^g--~8_w