已知数列{an}满足a1=0,a2=2,且对任意m、n∈N都有a(2m-1)+a(2n-1)=2a(m+n-1)+2(m-n)^2(1)求a3,a5(2)设bn=s(2n+1)-a(2n-1)(n∈N+),证明:{bn}是等差数列(3)设cn=(a(n+1)-an)q^(n-1)(q≠0,n∈N+),求数列{cn}的前n项和sn以上、
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