已知数列{An}满足A1=1,An+1={1/2An+n-1,n为奇数,An-2n,n为偶数},记Bn=A2nn∈N*求数列{Bn}的通项公式(提示:Bn+1=A2(n+1)=A(2n+1)+1)设Cn=(2^2n-1 -1)Bn²,数列{Cn}的前n项和为Sn,若对任意n属于N*,不等式
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