英文命名为:(S)-2-(2,2-dimethyl-5-oxo-1,3-dioxolan-4-yl)acetic acid是chemdraw自动生成的求中文命名.
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/29 02:17:16
xŒJ@_f&o6MHG+ЂŃ
"oӤ
= 8`3F(1O_ MKnS ԌI[ֺ2^xr%{hμ=.lxoemwi/\4
IVT{l;kE?Iu 0Ub_a }%h:I \C6 VVMB! жD8v05 LXTOsxU MG0F!fNx+`듅|4$:0i"dYu߿頿tr8x
如;Cu2O命名为氧化亚铜 应为2CuO CuO命名为氧化铜
VB中 Option ExplicitPrivate Sub Form_Click()Dim 5Fg Integer (1)Dim L * og As Long (2)Dim s - ig As Single (3)Dim dob_ As Double (4)Dim _Name AS String (5)Dim bln@ Frag As Boolean (6)Dim do As Data (7)End Sub电脑上的提示
英文命名为:(S)-2-(2,2-dimethyl-5-oxo-1,3-dioxolan-4-yl)acetic acid是chemdraw自动生成的求中文命名.
请帮忙解释下面语句意思-2'填写遗漏值 Dim n As Integer Dim arrR() As Integer, arrB() As Integer ReDim arrR(5), arrB(5) Dim r As Range Dim k As Long Dim t As Integer arrR(0)
0402 Private Sub Command1_Click() Dim a As Single,b As Single Dim c As Single,d As Single Dim m A0401Private Sub Form_Load()Dim x As Long,s As Stringx = InputBox(输入一个整数(1~40000))If x Mod 2 = 0 Thens = 偶数Elses = 奇数End IfMsgBo
(CH3CH2)2CHCH3的正确命名为?请写出解题过程~
英语翻译/com obtain nodes' information*GET,NTOT,NODE,0,COUNT*GET,Nmin,NODE,0,num,min*GET,Nmax,NODE,0,num,max*DIM,XY,ARRAY,NTOT,2*dim,nv,array,ntot*dim,nmold,array,ntot*dim,nheat,array,ntot*dim,ncenter,array,ntot*dim,ncon1,array,ntot*dim,ncon2,arr
VB编程,一元二次方程a*x^2+b*x+c=0的根Dim a As Double Dim b As Double Dim c As Double Dim delta As Double Dim x1 As Double Dim x2 As Double a = Val(Text1.Text) b = Val(Text2.Text) c = Val(Text3.Text) delta = b * b -
程序阅读,程序功能是什么Private Sub Command1_Click()Dim s%,n%Dim a As Stringn=0a=InputBox(“Please input a number:”)For s=1To Len(a)If(func(Val(Mid(a,s,1)))) Then n=n+1NextPrint nEnd SubPrivate Function func(x%) As BooleanIf(x Mod 2=0)
【有机化学】系统命名为cis-2-chlorocyclopropane和trans-2-chlorocyclopropane的化合物是什么?RT
(CH3CH2)2CHCH3的系统命名的正确命名为 列出结构式
该化合物该怎么命名?书上有命名为4-甲基-2-戊胺的?
如图(II)式为什么命名为2-硝基萘?而不是3-硝基萘?
CH3-CH(C2H5)-CH(C2H5)-CH3命名为:2,3-二乙基丁烷,是否正确?
private sub command1_click( ) dim a a=array(1,2,3,4) j=1:s=0 for i=4 to 1 step -1 s=s + a(i)*j j=
Dim a(1 To 10) As Integer Dim i As Integer a(1) = 1 For i = 2 To 10 a(i) = a
用vb 求π Private Sub Form_Click()Dim i As Long,pi As Double,k As Integer,m As Doublei = 1k = 1pi = 0m = 1While (m > 0.00001)m = 1 / (2 * i - 1)pi = pi + k * mi = i + 1k = -kWendPrint π ; 4 * piEnd SubPrivate Sub Form_Click()Dim pi,c,s As Single
dim a(3,2) as integer a(3,2)啥意思a(j,i)呢