设数列{An}的前n项和为Sn=2An-2^2 (1)证明{A(n+1)-2A(n)是等比数列 (2)求A(n)的通项公式

来源:学生作业帮助网 编辑:作业帮 时间:2024/08/25 08:08:09
xŒN@_m6gJgX`CHHhR5Q7x4-= lB 9tog[o5ӹyQ<:9/ Keόeڣ4\Gr|רi3pS|$W~+.rOD:8[mNMM*aMPHS]"Άb> 6l@V(1ͧʍR':fP>bu4Љ=Ӛx0ډu&[$`PP(̧,ϰ[1M}L#WV@\iUk!K&셻t'efzMfnJ `a+ ~//vc
设数列an的前n项和为Sn,若Sn=1-2an/3,则an= 数列{an},中,a1=1/3,设Sn为数列{an}的前n项和,Sn=n(2n-1)an 求Sn 设数列{an}的前n项和为sn=n^2,求a8 设数列{an}的前n项和Sn=2(an-3),证明{an}为等比数列,并求通项公式 已知数列{an}的前n项和为Sn,an+Sn=2,(n 已知数列{an}的前n项和为Sn,满足an+Sn=2n. (Ⅰ)证明:数列{an-2}为等比数列,并求出an;已知数列{an}的前n项和为Sn,满足an+Sn=2n.(Ⅰ)证明:数列{an-2}为等比数列,并求出an;(Ⅱ)设bn=(2-n) 设数列an的前n项和为Sn,满足an+sn=An^2+Bn+1(A不等于0)an为等差数列,求(B-1)/A 设数列an的前n项和为Sn,且2an=Sn+2n+1 求a1 a2 a3 求证:数列{an+2}是等比数列 求数列{n*an}的前n项和Tn 设数列an的前n项和为Sn,且2an=Sn+2n+1 求a1 a2 a3 求证:数列{an+2}是等比数列 求数列{n*an}的前n项和Tn 正数列{an}的前n项和为sn,且2根号sn=an+1 1、求an 2、设bn=1/an• an正数列{an}的前n项和为sn,且2根号sn=an+11、求an2、设bn=1/an• an+1,求{bn}的前n项和 数列{an}的通项公式an=log2(n+1)-log2(n+2),设{an}的前n项和为Sn,则使Sn 数列{an}的通项公式an=log2(n+1)-log2(n+2),设{an}的前n项和为Sn,则使Sn 设数列{an}的前n项和为Sn,若Sn=1-2/3an,n∈N*,则an= 设数列an的首项a1等于1,前n项和为sn,sn+1=2n设数列an的首项a1等于1,前n项和为sn,sn+1=2n 求:设数列 {an}的前n项和为Sn,数列{Sn}的前n项和为Tn,满足Tn=2Sn一n²,n∈求:设数列 {an}的前n项和为Sn,数列{Sn}的前n项和为Tn,满足Tn=2Sn一n²,n∈N 设数列{an}的前n项和为Sn,且对任意正整数n,an+Sn=4096(2)设数列{log an}的前n项和为Tn,对数列{Tn},从第几项起Tn 设数列{an}的前n项和为Sn,若a1=1,Sn=2an+Sn+(n∈N+),则a6= 一道关于数列 已知数列{An}的前n项和为Sn,Sn=3+2An,求An