2x+y=4/3,6x+3y=4解的情形
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/26 03:17:12
x)3Ю5716^,_|V˳֧{$W_`gC/|cɓM|Ehx`;Pγ9Ϧ/x6uPγ_ltB˹^6- T
Ty=:p>P춧:]|$ف B
2x+y=4/3,6x+3y=4解的情形
解方程组2x+3y=4,5x+6y=7,并将其解与方程组3x+4y=5,6x+7y的解进行比较,你能得出什么结论?上述方程推广为一般情形,并求其解.上面的方程组解出来都是x=-1,y=2
解方程组 10(x-y)=3(x+y)+15 6(x+y)=4(2x-y)+1610(x-y)=3(x+y)+156(x+y)=4(2x-y)+16分开的。
{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1
x+y/2+x-y/3=6,4(x+y)-3(x-y)=-20
{(x+y)/2+(x-y)/3=6 4(x+y)-3(x-y)=-20
4(x+y)-3(x-y)=-20,2/x+y+3/x-y=6
(x+y)/2- x-y/2=6 3(x+y)=4(x-y)
x+y/3+x-y/2=6 4(x+y)-2(x-y)=40
解二元一次方程组:3(x+y)-4(x-y)=4,x+y/2+x-y/6+1x+y/2+x-y/6+1=1
(x-y) (x-2y)+(x+2y) (x-3y)-2(x-3y) (x-4y)=
4x-(2x+y+16)/2=-6y 2x+3y=7-x-2y4x-(2x+y+16)/2=-6y 2x+3y=7-x-2y求方程组的解
x^2+4y^2-6x+4y+10=0,求x^4-y^4/(x+2y)(x-2y)*x+2y/xy^2+y^3除以(x^2+y^2/y)^2的值
已知x-y=1,求[(x+2y)^2+(2x+y)(x-4y)-3(x+y)(x-y)]除以y的值大神们帮帮忙
已知x-y=1,求[(x+2y)²+(2x+y)(x-4y)-3(x+y)(x-y)]÷y的值
化简求值:已知x、y满足:x^2+y^2-4x+6y+13=0 求代数式 的值.(3x+y)^2-3(3x-y)(x+y)-(x-3y)(x+3y)急用!
求5x-2y=x-y=4x-3y-2的解
3(x+y)+4(x-y)=36 2(x+y)=-10的解!