2009(22x-35)=9―2008(35―22x)
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/08 06:58:04
x)320|Ȩ^c{:m-5L
[ MAl\MR> lH5if<7Y`}p=@1M[K4@TBUA`4@RrckbfV$ف R[vs
2009(22x-35)=9―2008(35―22x)
2009(22x-35=9-2008(35-22x)?
35道.符号^代表平方.读起来就是(X的平方).1,x^-x-202,x^-9x+203,x^-9x-204,x^+9x+205,x^-18x+326,x^+14x-317,x^+18x+328,x^+14x-329,x^+19x+4810,x^+47x-4811,x^+13x-4812,x^+2x-4813,x^+26x+4814,x^-22x-4815,x^+17x+7216,x^+21x-10017,x^-x-7218,x
2009(22x-35)=9-2008(35-22x)
2009(22X-35)=9-2008(35-22X)
x*x*x*x+2008x*x+2007x+2008(提示:x*x*x-1=(x-1)*(x*x+x+1))
已知x+1/x=2,求(x^2008+x^-2008-2)/(x^2009+x^-2009)
已知 ,1+x+x^2=0,则x^2010+x^2009+x^2008+^(省略符号)+x+1=
|2008-x|+(根号x-2009)=x
实数X,Y满足(2X-3Y)^2+X^2+6X+9=0,则Y=?(X-Y)^2009=?
已知实数x满足|2008-x|+根号x-2009=x,求x-2008²的值.
已知x+1/x=2,求(x^2008+ x^-2008 -2)/(x^2009 +x^-2009)
x^2008+x^(-2008)-2/x^2009-x^(-2009)x+1/x=2
计算1/x(x+1)+1/(x+2)(x+1).+1/(x+2008)(x+2009)并求当x=1时,该代数式的值
已知实数x满足(绝对值)/2008-x/+√x-2009=x.求x-2008^2的值
已知x满足(2008-x)的绝对值+根号(x-2009)=x,求x-2008^2
求函数f(x,y)=x×x×x-y×y×y+3×x×x+3×y×y-9x的极值
(1)解方程:1/X+1/X(X+1)+1/(X+1)(X+2)+1/(X+2)(X+3)+.+1/(X+9)(X+10)=0(2)计算:1/(X+2)+1/(X+1)(X+3)+1/(X+2)(X+4)+.+1/(X+2007)(X+2009)一楼的:题没有错唉~二楼的: