y=log2(3-x)与y=log3(3/3x+4)的值域是什么?
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y=log2(3-x)与y=log3(3/3x+4)的值域是什么?
y=log2(x)+1/log3(3x+2) 的值域
log2^(log3^x)=log3^(log4^y)=0则x+y=
若log2(x)=log3(y)=log5(z)
求下列函数的定义域y=log2^(3-x) y=log3^3/3x+4
log2 3=x,log3 2√6/3=y,则x+2y的值为
y=log3(9/x)×log3 3x求值域!
一道高一数学题对数log2,详见补充已知log2[log1/2(log2^x)]=log3[log1/3(log3^y)]=log5[log1/5(log5^z)]=0,试比较x,y,z的大小?
log2(3)+log3(5)+log3(2)=?
已知log2[log3(log4x)]=log3[log4(log2y)]=0,求x+y
已知log2(log3(log4x))=log3(log4(log2y))=0,求x+y的值
已知:log2[log3(log4x)]=log3[log4(log2y)]=0 求x+y的值
log2[log3(log4x)]=log3[log4(log2y)]=0求x+y的值,
求函数y=log2的x次方+1/log3的(3x-2)的定义域
(log2 6)×(log3 6)-(log2 3+log3 2)=
(log2 6)×(log3 6)-(log2 3+log3 2)=
求下列函数的定义域(1)y=1/log2 X(2) y=log7(1/1-3x)(3) y=√log3 X
log2(3)*log3(2)=?