x^2+4y^2-2xy+12y+12=0,求x^y的值
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因式分解:12xy^2(y-x)+xy^3(x-y)+4x^2y(x-y)
X×X-2XY-Y×Y+2X-2Y+2=02X×2X-4XY-2Y×2Y+3X-3Y+4=0X×X+2XY+Y×Y+X+Y-56=0X×X-2XY+Y×Y-X+Y-12=0X×X-3XY+Y×Y=-13X×3X-XY+3Y×3Y=13 两个在一起的方程之间有所联系(要求一步一步写出来)
(12x^2y-8xy^2+16xy)/-3x+2y-4=?
(12x^2y-8xy^2+16xy)/-3x+2y-4=?
若x+y=4,x^3+y^3=(x+y)(x^2-xy+y^2)z,求x^3+12xy+y^3的值.
已知X+Y=3,XY=-1,求2(X-Y)^4-9(X-Y)^2+12XY
x^2+xy=12,xy+y^2=15,求(x+y)^2-(x+y)(x-y)
已知x-xy=20,xy-y=12,则x-y= ,-2xy+x+y=
已知x-xy=20 xy-y=12,则x-y=( ),x+y-2xy=( ).
已知:x-xy=20,xy-y=12,则x-y=...,-2xy+x+y=...
已知x-xy =21,xy-y=-12,分别求式子x-y与x-2xy +y
4/X+1/Y=2,XY=-1,求代数式4Y-X/X-2Y/(x+2y-12Y²/x-2y)的值
4x^2y+12xy+9y分解因式
已知X+Y=4,XY=-12那么X^2+Y^2= X^2-XY+Y^2= (X-Y)^2=
已知xy=-2,x+y=3,求代数式(4xy+12y)+[7x-(3xy+4y-x)]的值
解方程组:xy/x+y=-6(1) 2xy/x+2y=12(2)
计算:12xy^2/(x+y) * (x^2 - y^2)/4xy
12xy^2/x+y除以4xy/x^2-y^2