(1)2010×(1-1/2)×(1-1/3)×(1-1/4)×·········×(1-1/2009)×(1-1/2010) 用简便算法 (2)已知 1/3-1/5=1/3*5*2 那么 1/3*5+1/5*7+1、7*9+···+1、19*21(2)已知 1/3-1/5=1/3*5*2 那么 1/3*5+1/5*7+1、7*9+·
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计算:(1/2+1/3+...+1/2011)*(1+1/2+1/3+...+1/2010)-(1+1/2+1/3+...+1/2011)*(1/2+1/3+...+1/2010)
计算(1-1/2-1/3-...-1/2010)*(1/2+1/3+..+1/2011)-(1-1/2-1/3-...-1/2011)*(1/2+1/3+...+1/2010)
(1—1/2)*(1-1/3)*(1-1/4)*...*(1-1/2010)*2010
1/(1*2010)+1/(2*2009)+...+1/(2010*1)-(2010/2011)*(1/1*2009+1/2*2008+...+1/2009*1)
计算1/1*2010+1/2*2009+1/3*2008+...+1/2010*1-2010/2011(1/1*2009+1/2*2008+...+1/2009*1)
(1/2011-1)(1/2010-1)(1/2009-1)……(1/3-1)(1/2-1)
用简便算法计算:(1-1/2-1/3-1/4-…-1/2010)×(1/2+1/3+1/4+…+1/2010)-(1-1/2-1/3-1/4-…-1/2010)(1-1/2-1/3-1/4-…-1/2010)×(1/2+1/3+1/4+…+1/2010)-(1-1/2-1/3-1/4-…-1/2010)×(1/2+1/3+1/4+…+1/2010)
1-1/2)+(1/2-1/3)+(1/3-1/4).(1/2009-1/2010) = 1-1/2+1/2-1/3+1/3-1/4.1/2009-1/2010答案=2009/2010
(1-1/2)*(1/3-1)*(1-1/4)*(1/5-1)…(1/2009-1)*(1-1/2010)等于多少
(1-2/1)3/1-1)(1-4/1)(5/1-1)…(2009/1-1)(1-2010/1)等于几?
计算:(1-1/2)(1/3-1)(1-1/4)(1/5-1)……(1-1/2010)(1/2011-1)
(1-1/2)*(1-1/3)*(1-1/4)*……*(1-1/2008)*(1-1/2009)*(1-1/2010)
(-1)的2010次方-(1/2)的-1次方.
2010*(1-1/2)*(1-1/3)*…*(1-1/2010)=?(*=乘号)
(1*2)/1+(2*3)/1+(3*4)/1+.+2010*2011/1
数学题(-1*1/2)+(-1/2*1/3)+(-1/3*1/4)+.(-1/2010*1/2011)
(2011/1-1)(2010/1-1)(2009/1-1)…(3/1-1)(2/1-1)
(1/2012-1)(1/2011-1)(1/2010-1)...(1/3-1)(1/2-1)咋算