数学题(-1*1/2)+(-1/2*1/3)+(-1/3*1/4)+.(-1/2010*1/2011)
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数学题(-1*1/2)+(-1/2*1/3)+(-1/3*1/4)+.(-1/2010*1/2011)
数学题(-1*1/2)+(-1/2*1/3)+(-1/3*1/4)+.(-1/2010*1/2011)
数学题(-1*1/2)+(-1/2*1/3)+(-1/3*1/4)+.(-1/2010*1/2011)
就是求 通项为-(1/n*1/(n+1))序列的和,
这个通项=-(1/n-1/(n+1))=1/(n+1)-1/n
所以序列和=1/2-1+2/3-1/2+3/4-2/3.+1/2011-1/2010=1/2011-1= -2010/2011