若数列an满足a1=√6,a(n+1)=√(an+6),如果lim（an）存在,求lim（an）n趋向于无穷,n属于N*,√是根号的意思谢谢

已知数列{an}满足a(n+1)=an+n,a1=1,则an= 数列{an}满足a1=2,a(n+1)=2an+n+2,求an 若数列{an}满足a1=√(6),an+1=√(an+6),(n∈N),如果lim(an)存在,求lim(an)n都趋向无穷大 已知数列{an}满足a1=5,a(n+1)=an+6n+6,则an= 数列an满足a1=1,a(n+1)=an/[(2an)+1],求a2010 已知数列{an}满足a(n+1)=an+lg2,a1=1,求an 数列[An]满足a1=2,a（n+1）=3an-2 求an 通项公式为an=a（n^2)+n的数列{an},若满足a1 若数列an满足a1=1,an+1=2^nan...若数列an满足a1=1,a（n+1）=2^n·an,则数列an的通项公式? 已知数列{An}满足A1=1,A(n+1)=6A(n)+1,求{An}通项公式 已知数列an中,满足a1=6a,a(n+1)+1=2[(an)+1],n属于N*,求数列an的通项公式 数列An满足A1=0,A(n+1)=(An-√3)/(√3An+1)则A2009= 若数列{An}满足A1=2,nA(n+1)-(n+1)An=2,则数列{An}的通项公式A后面的n都是下标 数列{An}满足A1=5,A2=5,A(n+1)=An+6A(n-1)(n≥2,n∈N*).若数列{A(n+1)+kAn}是等比数列已知数列{An}满足A1=5,A2=5,A(n+1)=An+6A(n-1)(n大于等于2,n属于整整数)若数列{A(n+1)+kAn}是等比数列.(1)求数列{An}的通项公式 (2) 【高考】若数列{an}满足,a1=1,且a(n+1)=an/1+an,证明,数列｛1/an｝为等差数列,并求出数列{an}的通...【高考】若数列{an}满足,a1=1,且a(n+1)=an/1+an,证明,数列｛1/an｝为等差数列,并求出数列{an}的通项公式 若数列an满足a1=√6,a(n+1)=√(an+6),如果lim（an）存在,求lim（an）n趋向于无穷,n属于N*,√是根号的意思谢谢 若数列an满足a1=0,a(n+1)=(an-3)/(√3an+1) n为自然数,则a20=? 数列{An}满足a1=1/2,a1+a2+..+an=n方an,求an