若数列an满足a1=0,a(n+1)=(an-3)/(√3an+1) n为自然数,则a20=?
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若数列an满足a1=0,a(n+1)=(an-3)/(√3an+1) n为自然数,则a20=?
若数列an满足a1=0,a(n+1)=(an-3)/(√3an+1) n为自然数,则a20=?
若数列an满足a1=0,a(n+1)=(an-3)/(√3an+1) n为自然数,则a20=?
题目打错了吧……
a(n+1)=(an-√3)/(√3an+1)
a1 = 0 ,a2 = -√3 ,a3 = √3 ,a4 = 0
3个一周期,a20 = a2 = -√3
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