求cos5π/12sinπ/12
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求cos5π/12sinπ/12
sinπ/12cos5π/12等于
为什么cos5π/12等于sinπ/12
cos5π/12=sinπ/12 怎么算的?
把下列三角函数值从小到大排列起来:sin4/5π -cos5/4π sin32/5π cos5/12π求函数y=sin(π/6-x/3),x∈[-2π,4π]的单调递增空间.
(sin5π/12+cos5π/12)(sinπ/12-cosπ/12)
(sin5π/12-sinπ/12)(cos5π/12+cosπ/12)=?
cos5/12πcosπ/12+cosπ/12sinπ/6=?
sinπ/8*cos5π/8
sin派/12*cos5派/12
(sina5π/12+cos5π/12)(sin5π/12-cos5π/12)
已知sin(α+β)=3/5,sinβ=1/2,α+β,β均为锐角,求sinα的值.已知sin(α+β)=3/5,cos(α-β)=1/3,α+β,α-β均为锐角,求sin2α、cos2β.求[(sin5π/12)+(cos5π/12)]·[(sin5π/12)-(cos5π/12)]的值.求1+2cos²θ-cos2
sin(-4/3π)+cos5/6π=
cos5分之π×cos5分之2π
cosπ/12*cos5π/12结果是1/4
cos5π/12-根3sin5π/12过程
把下列三角函数值从小到大排列起来:sin4/5π,-cos5/4π,sin32/5π,cos5/12π.
计算cos5分之π+cos5分之2π+cos5分之3π+cos5分之4π