sin(-4/3π)+cos5/6π=

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sin(-4/3π)+cos5/6π=
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sin(-4/3π)+cos5/6π=
sin(-4/3π)+cos5/6π=

sin(-4/3π)+cos5/6π=
sin(-4/3π)+cos5/6π
=sin(2/3π)+cos5/6π
=√3/2-√3/2
=0

sin(-4/3π)+cos5/6π
=sin(2/3π)-cos1/6π
=sin(π/3)-sin(π/2-π/6)
=sin(π/3)-sin(π/3)
=0