已知f(x-2)=ax^2-(a-3)x=a-2(其中a为负整数)函数f(x)过点(m-2,0)已知f(x-2)=ax^2-(a-3)x+a-2(a为负整数)函数f(x)过点(m-2,0)(m属于R)1.求f(x)解析式设q(x)=f(f(x)),F(x)=p-q(x)+f(x),是否存

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