数列an满足a1=1,an= 根号【 2*a(n-1)的平方 +1】（都在根号内）a1=1,a2=根号3,a3=根号7,猜想an=根号【2^n -1】,写出用数学归纳法推出的具体过程.

已知数列an满足a1=1,1/an+1=根号1/an^2+2,an>0,求an 数列an满足an+1=根号(an^2+1)+an,a1=a>0,求an通项公式 数列{An}满足a1=1/2,a1+a2+..+an=n方an,求an 已知数列{an}满足a1=1,1/an+1=根号1/an62+2,an>0,求an是根号【1/(an^2+2)] 已知数列an满足a1=0,an+1=an-根号3/根号3an+1,则a2012= 数列{an}满足a1=1,an+1*根号（1/an^2+4)=1,S2n+1-Sn 已知数列{an}满足,a1=2,a(n+1)=3根号an,求通项an数列{an}满足:an>0,且根号下Sn=an+1/4,求通项an 数列{an}满足a1=1 an+1=2n+1an/an+2n 数列an满足a1=2,an+1=4an+9,则an=? 数列｛an｝满足a1=1,且an=an-1+3n-2,求an 已知数列{an}满足an+1=2an+3.5^n,a1=6.求an 数列an满足a1=2,an+1=an²求an 数列an满足a1=2,an+1=an²求an 已知数列满足a1=1,根号an-1-根号an=根号anan-1,求an 数列{an}满足a1=1,an+1=根号(an^2+2)(n属于N*),则该数列的通项公式an= 设数列｛an}满足a1=2,an+1=an+1/an(n=1,2,3.),证明：an>根号下（2n+1).急用 数列{an}的各项均为正数,且满足an+1=an+（2根号an）+1,a1=2,求an 已知数列{an}满足a1=1 an+1=an/(3an+1) 则球an