以知a1=2,an+1=2an+3,(n+1和n+3在a的下面),求an的通项公式?求数列nan的前n项的和Sn...

数列｛an},a1=1,an+1=2an-n^2+3n,求｛an｝. an+1 ,n+1是下表 ,an+1=an^3 a1=2 ,求an 在数列an中,a1=2 an+1=an+3n则an= 数列｛an｝满足a1=1,且an=an-1+3n-2,求an 已知{an}满足a1=1.an=3*n+2An-1,求an 数列{An}满足a1=1/2,a1+a2+..+an=n方an,求an 数列an满足a1=1/3,Sn=n(2n-1)an,求an 数列{an},a1=3,an*a(n+1)=(1/2)^n,求an 已知数列｛an｝中,a(n+1)=an+2^n,a1=3,求an an=a1+(n-1)d 和Sn=n(a1+an)/2中an是什么意思? an=a1+(n-1)d 和Sn=n(a1+an)/2中an是什么 数列{an}满足a1=1 an+1=2n+1an/an+2n 数列{an}中,a1=1,an+1/an=n/n+2,求an 在｛an｝中,a1=1,an+1=3an+2n,试求｛an｝的通项an 一道数学题、、数列{an}：a1=4,an=3an-1+2n-1,n≥2求an. 数列{an}满足a1=1,an=3n+2an-1(n≥2)求an 数列a1=-1,an+1=2an+4*{3}^{n-1}a1=-1,an+1=2an+4*{3}^{n-1},求an 2.a1=1,an+1=3an+(2^n),则an=?3.