已知数列{an}的前n项和为Sn=n^2+1,数列{bn}满足:bn=2/(an+1),且前n项和为Tn,设Cn=T(2n+1)-Tn.若对n>=k时,总有Cn

来源:学生作业帮助网 编辑:作业帮 时间:2024/09/19 12:19:00
xQJ@Y&d&R2ZH, ERBhU(R.ҊjmcBw&s+nfs=3g<./M% _fIxzQ J|e bKO*/_=Ϊ˫q2q0?4.:&eS&a,{+=Y΢ь|ee#hܐ;աOp~B8T*އbžtfwN^R/8nY~sSm\\Rlduf;sSGIS;:$B0E]Җ4q8$̢Sei#8$#l83#A;"|X# Q$A 2AmP3ld,ZyG