{x+y=4,x+y/3-x/2=1
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{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1
x+y+2(-x-y+1)=3(1-y-x)-4-(y+x-1),x+y=?
(x-y) (x-2y)+(x+2y) (x-3y)-2(x-3y) (x-4y)=
化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1
先化简 再求值 (2x-y)(y+x)-(x-2y)(2y+x)-(-3y+x)^2其(√x+1)+y^2+4=-4y
已知x-y=1,求[(x+2y)^2+(2x+y)(x-4y)-3(x+y)(x-y)]除以y的值大神们帮帮忙
已知x-y=1,求[(x+2y)²+(2x+y)(x-4y)-3(x+y)(x-y)]÷y的值
9y=3x-(x-1),4(x+y)-(2x+4)=8y
若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值
4x(x-y)-(2x-3y)(2x-3y) x=1 y=-1
[(y-2x)(-2x-y)+4(x-2y)平方]/3y,其中x=1,y=-3
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
解二元一次方程组:3(x+y)-4(x-y)=4,x+y/2+x-y/6+1x+y/2+x-y/6+1=1
为什么(x-2y)(x+4y)-(x-2y)+3(x+4y)-3=(x-2y+3)(x+4y-1).
若x=-1/4,能否确定代数式(2x-y)(2x+y)+(2x-y)(y-4x)+2y(y-3x)的值?
若x+y=4,则多项式1/2(x+y)+4(x-y)-3(x-y)-3/2(x+y)-x+y值是()
先化简,再求值[2x的平方-(x+y)(y-x)][3(-x-y)(y-x)+4y的平方]其中x=三分之一y=1
[(2x+y)^2+(y+2x)(y-2x)-2y(4x-y)]/4y,其中x=1/2,y=1/3