log2(x^2+7)-log2(x+5)=3 那个2是底下的那个数
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/05 03:49:10
x)O7Ҩ36ԅM5m^6-~cѳdGY-gS7$铧QΆ;~,|墡`X[MΆ'LBQhkZThƶP=@ƚP
[Cg^4VB|w
/W$Nɼl_wl+@}|~qAb( ͮO
log2(x – 2 ) + 2 = log2(5)log2(x – 2 ) + 2 = log2(5)
log2(x – 2 ) + 2 = log2(5)log2(x – 2 ) + 2 = log2(5)
|2x-log2^x|
解2log2^(x-5)=log2^(x-1)+1
|[log2(x)]^2-3log2(x)+1|
化简:(log2(x/4))*(log2(x/2))
[log2 1]+[log2 2]+[log2 3]+[log2 4]+[log2 5]+...+[log2 1024]=?[x]表示不超过x的最大整数2为底 答案是8204
log2 5 x log2 5等于log2 25还是什么?
log2 (5-x)
log2 (5-x)
log2(5-x)
log2(5-x)
log2(2X-1)
log2(x^2)图像
log2(x-2)
log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1
log2(x^2+7)-log2(x+5)=3 那个2是底下的那个数
log2^(x^log2^x)=?