如何微分log2(log3 x),2和3都是底
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如何微分log2(log3 x),2和3都是底
log2(3)+log3(5)+log3(2)=?
解不等式log3(x+2)大于0和log2(x-3)小于1
解不等式log3(x+2)大于0和log2(x-3)小于1,
log2(6)*log3(6)-[log2(3)+log3(2)]的值
(log2 6)×(log3 6)-(log2 3+log3 2)=
log2(6)*log3(6)-[log2(3)+log3(2)]的值
(log2 6)×(log3 6)-(log2 3+log3 2)=
已知log3(2) =log2(3)^x .求x
log2(3)*log3(2)=?
(log3^2)(log2^3)=
log2^3乘log3^2
对数函数方程log3 2=log2 3^x
log3 2等于log2 3的x次方
(log2(3)+log8(9))x(log3(4)+log9(8)+log3(2))
log2 (3)和log3 (2)哪个大?log3 (4) 和log2 (3)呢
解方程log2【9^2-4】=log2【3^x-2】+3答案是log3【6】
解方程:log4{2log3[1+log2(1+3log2 x)]}=1/2