.若两个整数x,y使x2+xy+y2能被9整除,证明:x和y能被3整除
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/10 00:48:51
xj@(KS ]v@jQ
U)ZӃDحF}z*^=apȻH1bOrcbXn3h?#U{ȇ;dn|Zs.愁i;
U\xť~h,!A49̀ƀ *Ūa<4_5>y[G1*(^2n`N<u-I &tg_sVg"G,}*$]
若两个整数x,y使x2+xy+y2能被9整除,证明:x和y能被3整除.
.若两个整数x,y使x2+xy+y2能被9整除,证明:x和y能被3整除
x.y是整数,且5x-y能被3整除,求证10x2+23xy-5y2能被9整除
(x-y)(x2+xy+y2)
(x+y)(x2-xy+y2)
求方程7(x+y)=3(x2-xy+y2)的整数解.
整数x,y满足x2-y2=2xy,求x-y/x+y的值
因式分解x2+y2-xy-x-y+1
x2-4y2-3xy+y+x
若X2+Y2-2X-6Y+10=0 ,求(x2-y2)/xy的值
求方程x+y=x2-xy+y2的整数解拜托耐心讲解下.
满足方程x2+y2=2(x+y)+xy的所有整数解有几对
(x-y)(x2+xy+y2)-xy(y-x)
若2x+y=0则(x2+xy+y2)/(2xy-x2)的值
求证:(x2-xy+y2)3+(x2+xy+y2)3能被2x2+2y2整除
若x-y/x+y=2,则x2+2xy+y2/4xy=多少
4x2-y2/x2-2xy+y2 +(2x-y)/2x2-2xy
若x/y=2,求x2-2xy-3y2/x2-6xy-7y2的值