y=1/3sin(3x+π/7) ,x∈[0,+∞) 说明函数的图象可由正弦曲线经过怎样变化得到、主要是加上定义域是什么意思、别复制别人的答案
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已知sinx=3/5,x∈(π/2,π),求【sin(x+y)+sin(x-y)】/【cos(x+y)+cos(x-y)】的值
y=sin(x+π/3)周期
求导:y=3^(sin*1/x)
Y=SIN(3x-1)
y=sin(1/3x+π/4),x∈R的周期.
判断单调性 y=sin(x-π/6) y=sin(-2x+π/3)
y=|7sin(3x-5分之π)|
sinx=1/3,sin(x+y)=1,求sin(2y+x)=?
已知sinx=1/3,sin(x+y)=1,则sin(2y+x)=
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(cosx)^2-(cosy)^2=1/3求sin(x+y)*sin(x-y).
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y=sin(x-π/6) 和 y=1/2sin(π/3-2x) 的单增区间,
Sin x-sin y=2/3 cos x-cos y=1/2 求cos(x-y)
cos(x-y/2)=-1/9,sin(x/2-y)=2/3,π/2
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sin^2x+cos^2y=1/2 求3sin^2x+sin^2y的最值