∫(tanx)^1/4 dx/sin^2x

∫sin^2x(1+tanx)dx ∫(tanx)^1/4 dx/sin^2x 1.∫ [sin(2x)]^2 dx 2.∫(1-tanx)/(1+tanx) dx 求∫tanx/(1-(tanx)^2)dx ∫(tanx)^4 dx ∫dx/(1+tanx) ∫(tanx)^2dx ∫ dx/[(1-cosx)sin²x] 令t=tanx/2怎么做 急 求不定积分∫((tanx)^4-1)dx, 求不定积分?∫(tanx-1)^2dx ∫(secx/1+tanx)^2dx ∫tanx(tanx＋1)dx 求积分 (tanx^2+tanx^4 )dx ∫dx/(1+tanX)=? tanx^2积分除了这种方法∫(tanx)^2dx=∫[(secx)^2-1]dx=tanx-x+C 求不定积分：∫(sin²7x/(tanx + cosx) dx, ∫dx/cos^2(tanx-1)^1/2 等于? ∫dx/cos^2(tanx-1)^1/2等于?