tanx=5/12,tany=4/3.x属于0,90,y属于180,270,求sin(x+y)
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tanx=5/12,tany=4/3.x属于0,90,y属于180,270,求sin(x+y)
tan(x+y)=tanx+tany吗
证明 (tanX+tanY)/(tanX-tanY)=(sin(X+Y))/(sin(X-Y))thanks
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高手进tanx+tany/tanx-tany=3/2 求tanx/tany?
COS(X加Y)=3/5,cos(x减y)=4/5.则tanx乘tany
x +y=90°,tanx*tany=?
求证tanx+tany/tanx-tany=sin(x+y)/sin(x-y)(详细步骤)
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tanx=2,tan(x-y)=-3/5,则tany=?
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已知tanx=1/4,tany=-3,求tan(x+y)的值
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