sin(2π/3+λ)=1/2,0
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sin0=0 sin(1/6π)=1/2sin(1/3π)=√3/2sin(1/2π)=1sin(2/3π)=√3/2sin(5/6π)=1/2sin(π)=0sin(-π)=0sin(-5/6π)=-1/2sin(-2/3π)=-√3/2sin(-1/2π)=-1sin(-1/3π)=-√3/2sin(-1/6π)=-1/2sin(7/6π)=-1/2sin(4/3π)=-√3/2sin(5/3π)=-√3/2sin(11/6π)=-1/
设α,β,γ∈(0,π/2)且(sinα)^2+(sinβ)^2+(sinγ)^2=1求函数y=(sinα)^3/sinβ+(sinβ)^3/sinγ+(sinγ)^3/sinα 的最小值.
化简sin(α+β)+sin(α-β)+2sinαsin(3π/2-β)=
sin²0+sin²1+sin²2+……+sin²180=
sin(2π/3+λ)=1/2,0
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sin((3π)/3-a)=sin(π+(1/2-a))=-(sin(1/2-a))=-cosa
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