(2+1)(2^1+1)(2^2+1)(2^3+1)(2^4+1)...(2^2n+1) 怎么算
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(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)+1/2^15
1 2 1 2 () () ()()
1+1/2^2
(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)+1/2^15=?
(2^2+1)*(2^4+1)*(2^8+1)*(2^16+1)*(2^32+1)
(1-1/2^2)(1-1/3^2)K(1-1/10^2)
(1-1/2^2)(1-1/3^2)K(1-1/10^2)
(1+1/2)(1+1/2^2)(1+1/2^4)^(1+1/2^32)
2、(1),(2)
(2+1)(2²+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)+1
(1)(2)
(1) (2)
(1)(2)
(1),(2).
(1)(2)
(1)(2)
(1)(2),
(1) (2)