k 2x+1已知lim（xsin——-——）=1,则k=?x x-1lim底下的x趋于无穷 已知lim（xsink/x减去2x+1/x-1）=1，则k=？

k 2x+1已知lim（xsin——-——）=1,则k=?x x-1lim底下的x趋于无穷 已知lim（xsink/x减去2x+1/x-1）=1，则k=？ lim(x→0)xsin *1/x^2 lim xsin(2/x) x→∞ lim(x趋向0)1-x^2-e^(-x^2)/xsin^3(2x) lim(x→∞)[sinx/x+xsin(1/2x)]答案是1/2.求过程 lim x趋于无穷,xsin(2x/1+x^2)= 求极限lim{[(sinx)/x]+xsin(1/2x)}x趋向无穷大, lim(x趋于无穷)xsin(3x/1+x^2)= lim(x->∞)[ xsin(2/x)+(cosx^2)/(x^2)] lim(x→∞) (xsin(1/x)+1/x(sinx)) lim(sinx/x+xsin(1/x)) = x->无穷 极限lim x 趋无穷(sin5x/x-xsin(2/x)) x趋近于无穷 lim [xsin(1/3x) ]=? lim x→∞ xsin(1/x)求极限 求lim(n→0)[sin2x/x-xsin(2/x)] lim x趋近于无穷xsin(k/x)-(2x+1)/(x-1) 等于1求k这个极限我不怎么会解~也不知道怎么用罗比达法则~ 求(x-tanx)/(xsin^2x)的极限lim(x趋于0)x^2e^(1/x^2) lim(x趋于0+)x^sinx 求当x趋于0时lim (1+x)^1/2-(1+x)^1/3/x;lim(xsin(1/x)+(1/x)sinx0的极限要过程,谢谢!