(m^2-4)(n^2-9)+24mn
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若m-n=4,mn=-1求(9-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)
(m^2-4)(n^2-9)+24mn
[(m+n)^2-4mn][(m-n)^2+4mn]+2(mn)^2
3(m^2n+mn)-4(mn-2m^2n)+mn.要有过程
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已知m-n=2,mn=1,求多项式(-2mn+2mn+3n)-(3mn+2n-2m)-(m+4n+mn)的值
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求(9-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn) 先化简,再求值
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(3m-2n)²+24mn
已知m-n=4,mn=2,求多项式(-2mn+2m+3n)-(3mn+2n-2n)-(m+4n+mn)的值
4-m²n²+2mn
已 知m-n=4,mn=-1,求:(-2mn+2m+3n)-(3mn+2n-2n)-(m+4n+mn)的值
已知m-n=4,mn=2,求多项式(-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)的值.
已知m-n=4,mn=-1,求(-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)的值.
若m-n=4,mn=-1,求(-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)
已知m-n=4,mn=-1,求(-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)的值