如何用Mathematica实现比如现在有这样一个式子:Product[Sum[f[ j ]/x[ i ]],{j, n}]], {i, k}] {c[1] (-1 + c[2]).(-n+1+c[n]} 当k=2,n=2时,上面的式子为 (f[1]/x[1]+f[2]/x[1]) (f[1]/x[2]+f[2]/x[2]) {c[1] (-1 + c[2])}
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![如何用Mathematica实现比如现在有这样一个式子:Product[Sum[f[ j ]/x[ i ]],{j, n}]], {i, k}] {c[1] (-1 + c[2]).(-n+1+c[n]} 当k=2,n=2时,上面的式子为 (f[1]/x[1]+f[2]/x[1]) (f[1]/x[2]+f[2]/x[2]) {c[1] (-1 + c[2])}](/uploads/image/z/10034499-3-9.jpg?t=%E5%A6%82%E4%BD%95%E7%94%A8Mathematica%E5%AE%9E%E7%8E%B0%E6%AF%94%E5%A6%82%E7%8E%B0%E5%9C%A8%E6%9C%89%E8%BF%99%E6%A0%B7%E4%B8%80%E4%B8%AA%E5%BC%8F%E5%AD%90%EF%BC%9AProduct%5BSum%5Bf%5B+j+%5D%2Fx%5B+i+%5D%5D%2C%7Bj%2C+n%7D%5D%5D%2C+%7Bi%2C+k%7D%5D+%7Bc%5B1%5D+%28-1+%2B+c%5B2%5D%29.%28-n%2B1%2Bc%5Bn%5D%7D+%E5%BD%93k%3D2%2Cn%3D2%E6%97%B6%2C%E4%B8%8A%E9%9D%A2%E7%9A%84%E5%BC%8F%E5%AD%90%E4%B8%BA+++++%28f%5B1%5D%2Fx%5B1%5D%2Bf%5B2%5D%2Fx%5B1%5D%29++%28f%5B1%5D%2Fx%5B2%5D%2Bf%5B2%5D%2Fx%5B2%5D%29++%7Bc%5B1%5D+%28-1+%2B+c%5B2%5D%29%7D)
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