复合函数的单调区间求y=F(X)=根号下8-2x-x方的单调区间.标准答案是这样的:由题意,函数F(x)的定义域为【-4,2】设y=f(u)=根号下u,u=g(x)=8-2X-X方二次函数u=g(x)=-(x+1)方+9的递增区间是(-无穷,-1】,递
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![复合函数的单调区间求y=F(X)=根号下8-2x-x方的单调区间.标准答案是这样的:由题意,函数F(x)的定义域为【-4,2】设y=f(u)=根号下u,u=g(x)=8-2X-X方二次函数u=g(x)=-(x+1)方+9的递增区间是(-无穷,-1】,递](/uploads/image/z/10083308-68-8.jpg?t=%E5%A4%8D%E5%90%88%E5%87%BD%E6%95%B0%E7%9A%84%E5%8D%95%E8%B0%83%E5%8C%BA%E9%97%B4%E6%B1%82y%3DF%28X%29%3D%E6%A0%B9%E5%8F%B7%E4%B8%8B8-2x-x%E6%96%B9%E7%9A%84%E5%8D%95%E8%B0%83%E5%8C%BA%E9%97%B4.%E6%A0%87%E5%87%86%E7%AD%94%E6%A1%88%E6%98%AF%E8%BF%99%E6%A0%B7%E7%9A%84%EF%BC%9A%E7%94%B1%E9%A2%98%E6%84%8F%2C%E5%87%BD%E6%95%B0F%28x%29%E7%9A%84%E5%AE%9A%E4%B9%89%E5%9F%9F%E4%B8%BA%E3%80%90-4%2C2%E3%80%91%E8%AE%BEy%3Df%28u%29%3D%E6%A0%B9%E5%8F%B7%E4%B8%8Bu%2Cu%3Dg%28x%EF%BC%89%3D8-2X-X%E6%96%B9%E4%BA%8C%E6%AC%A1%E5%87%BD%E6%95%B0u%3Dg%28x%29%3D-%28x%2B1%29%E6%96%B9%2B9%E7%9A%84%E9%80%92%E5%A2%9E%E5%8C%BA%E9%97%B4%E6%98%AF%EF%BC%88-%E6%97%A0%E7%A9%B7%2C-1%E3%80%91%2C%E9%80%92)
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来源:学生作业帮助网 编辑:作业帮 时间:2024/07/11 22:14:42