(1+0.228-0.21)×(0.228-0.21+223)-(1+0.228-0.21+0.2003)×﹙0.228-0.21)(能巧算的就巧算)

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(1+0.228-0.21)×(0.228-0.21+223)-(1+0.228-0.21+0.2003)×﹙0.228-0.21)(能巧算的就巧算)
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(1+0.228-0.21)×(0.228-0.21+223)-(1+0.228-0.21+0.2003)×﹙0.228-0.21)(能巧算的就巧算)
(1+0.228-0.21)×(0.228-0.21+223)-(1+0.228-0.21+0.2003)×﹙0.228-0.21)
(能巧算的就巧算)

(1+0.228-0.21)×(0.228-0.21+223)-(1+0.228-0.21+0.2003)×﹙0.228-0.21)(能巧算的就巧算)
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(1+0.228-0.21)*(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)*(0.228-0.21)巧算?写清思路 (1+0.228-0.21)*(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)*(0.228-0.21)要求简便运算 (1+0.228-0.21)x(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)x(0.228-0.21) (1+0.228-0.21)*(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)*(0.228-0.21)如何巧算?写清巧算步骤. (1+0.228-0.21)×(0.228-0.21+223)-(1+0.228-0.21+0.2003)×﹙0.228-0.21)(能巧算的就巧算) (1+0.228-0.21)x(0.228-0.221+0.2003)-(1+0.228-0.21+0.2003)x(0.228-0.21)怎么样巧算 (1+0.228-0.21)×(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)×(0.228-0.21)为什么这么做啊(1+0.228-0.21)×(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)×(0.228-0.21)=(1+0.228-0.21)×(0.228-0.21)-(1+0.228- (1+0..228-0.21)x(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)x(0.228-0.21)简便方法计算简便方法 (1+0.228-0.21)×(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)×(0.228-0.21)简便运算,要写出具体过程 (1+0.228-0.21)×(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)×(0.228-0.21)简便解法这是预初一的题,但是不要告诉我去用计算机去做, 巧算(2-1/2)×(2-2/3)×(2-3/4)×……×(2-2002/2003)巧算:(2-1/2)×(2-2/3)×(2-3/4)×……×(2-2002/2003)(1+0.228-0.21)*(0.228-0.21+0.20030)-(1+0.228-0.21+0.2003)*(0.228-0.21)解方程:7(x-3)=9+X21-x=1.5(9+x) 坎贝尔太空计划0.22有MJ吗还有0.22和0.21的区别有什么 (1+0.21+0.32)*(0.21+0.32+0.43)-(1+0.21+0.32+0.43)*(0.21+0.32)要怎么简算, 计算(1+0.21+0.32)x(0.21+0.32+0.43)-(1+0.21+0.32+0.43)x(0.21+0.2) 计算(1+0.21+0.32)x(0.21+0.32+0.43)-(1+0.21+0.32+0.43)x(0.21+0.2) (1+0.21+0.32)*(0.21+0.32+0.43)-(1+0.21+0.32+0.43)*(0.21+0.32) 0.21除以9+0.22除以9+0.23除以9+0.24除以9 简便计算 指数,对数比较大小(0.21)3.5次方 与 (0.22)3.1次方要说明怎算..