解一道数学题(求值题)2^m=6,4^n=2,求2^(2m-4n=3)的值是2^(2m-4n+3)
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解一道数学题(求值题)2^m=6,4^n=2,求2^(2m-4n=3)的值是2^(2m-4n+3)
解一道数学题(求值题)
2^m=6,4^n=2,求2^(2m-4n=3)的值
是2^(2m-4n+3)
解一道数学题(求值题)2^m=6,4^n=2,求2^(2m-4n=3)的值是2^(2m-4n+3)
2^m=6,4^n=2,求2^(2m-4n+3)的值
2^(2m)=36
4^n=2
2^(2n)=2
2^(4n)=4
2^(2m-4n+3)
=2^(2m)/2^(4n)*2^3
=36/4*8
=72
2^(m)=6 4^(n)=2^(2n)=2
2^(2m-4n+3)
=2^(2m)*2^(-4n)*2^(3)
=2^(2m)*{2^(2n)}^(-2)*2^(3)
代入 可得到 值为12
2^m=6,4^n=2,求2^(2m-4n=3)应该是2^m=6,4^n=2,求2^(2m-4n-3)吧,因为4^n=2,所以n=1/2
2^(2m-4n-3)
=2^(2m-2-3)
=2^(2m-1)
=2^2m/2
=(2^m)^2/2
=6^2/2
=18
因为4^n=2,所以等于2^2n=2,又因为2^m=6,所以2^m/2^2n=3,即2^(m-2n)=3
因为m-2n的结果是与2m-4n的结果相同的,所以原式可以变为
2^(m-2n)*2^3=3*8=24
答案是72,四楼的正确,呵呵~~
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