(3y-6)分之(2y+5)=(2y-4)分之(5y-4)+2分之1

来源:学生作业帮助网 编辑:作业帮 时间:2024/07/06 23:27:25
(3y-6)分之(2y+5)=(2y-4)分之(5y-4)+2分之1
x)05|dgQ-5 FMR>Z lȲǨn{^{暂&@#0C(VlhdC=0m@I#@ 8@mVQyx:<ȃiC7T+.-0iadd3HdS! *A>;~ijΆ'>[Ϧ/xn޳^,_g_\g }h [

(3y-6)分之(2y+5)=(2y-4)分之(5y-4)+2分之1
(3y-6)分之(2y+5)=(2y-4)分之(5y-4)+2分之1

(3y-6)分之(2y+5)=(2y-4)分之(5y-4)+2分之1
2y+5/3y-6=5y-4/2y-4 + ½
2y+5/3y-6=2(5y-4)+2y-4/2(2y-4)
2y+5/3y-6=3y-3/y-2
(2y+5)×(y-2)=(3y-6)×(3y-3)
7y²-28y+28=0
(7y-14)(y-2)=0
y=2
2y-4=0
所以此题无实数解.