若:X^2-4X+Y+6Y+√ Z-3+13=0求(xy)^z的值
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若:X^2-4X+Y+6Y+√ Z-3+13=0求(xy)^z的值
若:X^2-4X+Y+6Y+√ Z-3+13=0求(xy)^z的值
若:X^2-4X+Y+6Y+√ Z-3+13=0求(xy)^z的值
题目出错了吧 应该是x^2-4x+y^2+6y+√(z-3)+13 = 0
即(x-2)^2+(y+3)^2+√(z-3) = 0
(xy)^z = (2*(-3))^3 = -216 啊
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