作业帮(1-m)(1-m)(6-m)+18+18-9(1-m)-4(6-m)-9(1-m)怎么提公因式?
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(1-m)(1-m)(6-m)+18+18-9(1-m)-4(6-m)-9(1-m)怎么提公因式?
(1-m)(1-m)(6-m)+18+18-9(1-m)-4(6-m)-9(1-m)怎么提公因式?
(1-m)(1-m)(6-m)+18+18-9(1-m)-4(6-m)-9(1-m)怎么提公因式?
=(1-m)^2(6-m)-4(6-m)-18(1-m)+36
=(6-m)[(1-m)^2-4]-18[(1-m)-2]
=(6-m)[(1-m)+2][(1-m)-2]+18(m+1)
=(6-m)(3-m)[-(m+1)]+18(m+1)
=(m+1)[18-(6-m)(3-m)]
=(m+1)(9m-m^2)
=m(m+1)((9-m)
化简|6-m|-|2m+1|+|m+5| (m
(1-m)(1-m)(6-m)+18+18-9(1-m)-4(6-m)-9(1-m)怎么提公因式?
(M/1):(M/0.
(((m>=1) & (m
m*m-5m-1=0则2m*m-5m+1/m*m
已知m*m+m-1=0,求m*m*m+2m*m-2005
m^2+m-6/m^2+2m+1÷m+3/m^+m·m^2-1/2-m 其中m=-1/2
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解方程：6/m-1+3/m=m+5/m(m-1)
先化简 再求值（3+m)(3-m)+m(m-6)-7,其中m=1/2
m^15+m^12+m^9+m^6+m^3+1
m^15+m^12+m^9+m^6+m^3+1
化简（m-1)(m+1)(m-1)
数学题(m-1)(m²+m+1)
计算 (m+1)(m²+m-1)