f(x)=Asin^2(ωx+φ)(A>0,ω>0,0<φ<π/2),y=f(x)得最大值为2,其图像相邻两对称轴距离为2.并过(1,2) (1)求φ(2)求f(1)+f(2)+.+f(2012)
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/21 00:27:34
![f(x)=Asin^2(ωx+φ)(A>0,ω>0,0<φ<π/2),y=f(x)得最大值为2,其图像相邻两对称轴距离为2.并过(1,2) (1)求φ(2)求f(1)+f(2)+.+f(2012)](/uploads/image/z/10177232-32-2.jpg?t=f%28x%29%3DAsin%5E2%28%CF%89x%2B%CF%86%29%28A%3E0%2C%CF%89%EF%BC%9E0%2C0%EF%BC%9C%CF%86%EF%BC%9C%CF%80%2F2%29%2Cy%3Df%28x%29%E5%BE%97%E6%9C%80%E5%A4%A7%E5%80%BC%E4%B8%BA2%2C%E5%85%B6%E5%9B%BE%E5%83%8F%E7%9B%B8%E9%82%BB%E4%B8%A4%E5%AF%B9%E7%A7%B0%E8%BD%B4%E8%B7%9D%E7%A6%BB%E4%B8%BA2.%E5%B9%B6%E8%BF%87%281%2C2%29+%281%29%E6%B1%82%CF%86%282%29%E6%B1%82f%281%29%2Bf%282%29%2B.%2Bf%282012%29)
xRN0~PV.ً/H t*1z!A5nK
zP8x~Rd9
],j7 -q7
/tjc@C_ZD/X/@Gb$i nǯONr(VN}` 5`(t5s&@74%\rd}$+V#ESD@(ٔ\qz{^3<GշBVT
U#pVD}Wދ=W
f(x)=Asin^2(ωx+φ)(A>0,ω>0,0<φ<π/2),y=f(x)得最大值为2,其图像相邻两对称轴距离为2.并过(1,2) (1)求φ(2)求f(1)+f(2)+.+f(2012)
f(x)=Asin^2(ωx+φ)(A>0,ω>0,0<φ<π/2),y=f(x)得最大值为2,其图像相邻两对称轴距离为2.并过(1,2) (1)求φ(2)求f(1)+f(2)+.+f(2012)
f(x)=Asin^2(ωx+φ)(A>0,ω>0,0<φ<π/2),y=f(x)得最大值为2,其图像相邻两对称轴距离为2.并过(1,2) (1)求φ(2)求f(1)+f(2)+.+f(2012)
(1)f(x)=Asin^2(ωx+φ)=A/2-A/2cos(2ωx+2φ)(A>0,ω>0,0<φ<π/2)得最大值为2,其图像相邻两对称轴距离为2.
所以A=2,相邻两对称轴距离为周期的一半即π/2w=2 w=π/4
f(x)=Asin^2(ωx+φ)=1-cos(πx/2 +2φ) 过(1,2) 代入有π/2 +2φ=π,φ=π/4
(2) 周期为4
f(1)+f(2)+.+f(2012)即2012/4=503个f(1)+f(2)+f(3)+f(4)的和
f(1)+f(2)+.+f(2012)=503×(2+1+0+1)=2012
函数f(x)=Asin(ωx+φ)(A>0 ω>0 -π/2
已知函数f(x)=Asin(ωx+φ)(A>0,ω>0,-π/2
急用::已知函数f(x)=Asin^2(ωx+φ)(A>0,0
已知函数f(x)=Asin(2x+φ) (A>0,0已知函数f(x)=Asin(2x+φ) (A>0,0
已知函数f(x)=Asin(ωx+φ)+a+1(A>0,ω>0,0
已知函数f(x)=Asin(ωx+φ)
已知函数f(x)=Asin(ωx+a)(A>0,ω>0,-π/2
函数f(x)=Asin(wx+φ),A>0,|φ|
已知函数f (x)=Asin(ωx=φ)(A>0,ω>0,|φ|
f(x)=Asin(ωx+φ) 怎么样根据图像判断A ω φ
已知函数f(x)=Asin(ωx+φ)+B(A>0,ω>0,|φ|
已知函数f(x)=Asin(ωx+φ)(A>0,ω>0,|φ|
已知函数f(x)=Asin(ωx+φ)(A>0,ω>0,|φ|
已知函数f(x)=Asin(ωx+φ)(A>0,ω>0,|φ|
已知函数f(x)=Asin(ωx+φ)(A>0,ω>0,|φ|
已知函数f(x)=Asin(ωx+φ)+m)(A>0,ω>0,|φ|
已知函数f(x)=Asin(ωx+φ)(A>0,ω>0,|φ|
已知函数f(x)=Asin(ωx+φ)(A>0,ω>0,|φ|