已知:如图,AD是△ABC的高,AD=1/2AB,CD=1/2AC,求证:AC=1/2BC
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![已知:如图,AD是△ABC的高,AD=1/2AB,CD=1/2AC,求证:AC=1/2BC](/uploads/image/z/10184132-20-2.jpg?t=%E5%B7%B2%E7%9F%A5%3A%E5%A6%82%E5%9B%BE%2CAD%E6%98%AF%E2%96%B3ABC%E7%9A%84%E9%AB%98%2CAD%3D1%2F2AB%2CCD%3D1%2F2AC%2C%E6%B1%82%E8%AF%81%3AAC%3D1%2F2BC)
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