已知函数f(x)=ax³+bx²-3x(a,b∈R),在点(1,f(1))处的切线方程为y+2=0.(1已知函数f(x)=ax³+bx²-3x(a,b∈R),在点(1,f(1))处的切线方程为y+2=0.(1)求函数f(x)的解析式;(2)若对于区间[-2,2]
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![已知函数f(x)=ax³+bx²-3x(a,b∈R),在点(1,f(1))处的切线方程为y+2=0.(1已知函数f(x)=ax³+bx²-3x(a,b∈R),在点(1,f(1))处的切线方程为y+2=0.(1)求函数f(x)的解析式;(2)若对于区间[-2,2]](/uploads/image/z/10190156-68-6.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%3Dax%26sup3%3B%2Bbx%26sup2%3B-3x%28a%2Cb%E2%88%88R%29%2C%E5%9C%A8%E7%82%B9%281%2Cf%281%29%29%E5%A4%84%E7%9A%84%E5%88%87%E7%BA%BF%E6%96%B9%E7%A8%8B%E4%B8%BAy%2B2%3D0.%281%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%3Dax%26sup3%3B%2Bbx%26sup2%3B-3x%28a%2Cb%E2%88%88R%29%2C%E5%9C%A8%E7%82%B9%EF%BC%881%2Cf%281%29%EF%BC%89%E5%A4%84%E7%9A%84%E5%88%87%E7%BA%BF%E6%96%B9%E7%A8%8B%E4%B8%BAy%2B2%3D0.%EF%BC%881%EF%BC%89%E6%B1%82%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F%EF%BC%9B%EF%BC%882%EF%BC%89%E8%8B%A5%E5%AF%B9%E4%BA%8E%E5%8C%BA%E9%97%B4%5B-2%2C2%5D)
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