设α,β为方程X^2-12X+9=0的两个根,求(α^3/2-β^3/2)/(α-β)的值急我说的是a的3/2次方不是二分之a的3次方,gjw921110
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![设α,β为方程X^2-12X+9=0的两个根,求(α^3/2-β^3/2)/(α-β)的值急我说的是a的3/2次方不是二分之a的3次方,gjw921110](/uploads/image/z/10192795-43-5.jpg?t=%E8%AE%BE%CE%B1%2C%CE%B2%E4%B8%BA%E6%96%B9%E7%A8%8BX%5E2-12X%2B9%3D0%E7%9A%84%E4%B8%A4%E4%B8%AA%E6%A0%B9%2C%E6%B1%82%28%CE%B1%5E3%2F2-%CE%B2%5E3%2F2%29%2F%28%CE%B1-%CE%B2%29%E7%9A%84%E5%80%BC%E6%80%A5%E6%88%91%E8%AF%B4%E7%9A%84%E6%98%AFa%E7%9A%843%2F2%E6%AC%A1%E6%96%B9%E4%B8%8D%E6%98%AF%E4%BA%8C%E5%88%86%E4%B9%8Ba%E7%9A%843%E6%AC%A1%E6%96%B9%EF%BC%8Cgjw921110)
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