高中数学三角函数的简单求导问题(2个方法得到答案不同,我有疑问)求函数Y=sin(x/2)*-cos(x/2)的导数解法一(答案):Y=-1/2sinx所以Y'=-1/2cosx解法二:Y=[sin(x/2)]'*-[cos(x/2)]+[sin(x/2)]*
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![高中数学三角函数的简单求导问题(2个方法得到答案不同,我有疑问)求函数Y=sin(x/2)*-cos(x/2)的导数解法一(答案):Y=-1/2sinx所以Y'=-1/2cosx解法二:Y=[sin(x/2)]'*-[cos(x/2)]+[sin(x/2)]*](/uploads/image/z/10247762-2-2.jpg?t=%E9%AB%98%E4%B8%AD%E6%95%B0%E5%AD%A6%E4%B8%89%E8%A7%92%E5%87%BD%E6%95%B0%E7%9A%84%E7%AE%80%E5%8D%95%E6%B1%82%E5%AF%BC%E9%97%AE%E9%A2%98%EF%BC%882%E4%B8%AA%E6%96%B9%E6%B3%95%E5%BE%97%E5%88%B0%E7%AD%94%E6%A1%88%E4%B8%8D%E5%90%8C%2C%E6%88%91%E6%9C%89%E7%96%91%E9%97%AE%EF%BC%89%E6%B1%82%E5%87%BD%E6%95%B0Y%3Dsin%EF%BC%88x%2F2%EF%BC%89%2A-cos%EF%BC%88x%2F2%EF%BC%89%E7%9A%84%E5%AF%BC%E6%95%B0%E8%A7%A3%E6%B3%95%E4%B8%80%EF%BC%88%E7%AD%94%E6%A1%88%EF%BC%89%EF%BC%9AY%3D-1%2F2sinx%E6%89%80%E4%BB%A5Y%27%3D-1%2F2cosx%E8%A7%A3%E6%B3%95%E4%BA%8C%EF%BC%9AY%3D%5Bsin%EF%BC%88x%2F2%EF%BC%89%5D%27%2A-%5Bcos%EF%BC%88x%2F2%EF%BC%89%5D%2B%5Bsin%EF%BC%88x%2F2%EF%BC%89%5D%2A)
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