数学对书问题log(2)3=a log(3)7=b 用a和b表示log(14)56

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数学对书问题log(2)3=a log(3)7=b 用a和b表示log(14)56
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数学对书问题log(2)3=a log(3)7=b 用a和b表示log(14)56
数学对书问题
log(2)3=a log(3)7=b 用a和b表示log(14)56

数学对书问题log(2)3=a log(3)7=b 用a和b表示log(14)56
a=lg3/lg2
b=lg7/lg3
a·b=lg7/lg2
log(14)56=lg56/lg14
=lg(7·2^3)/lg(7·2)
=(lg7+3lg2)/(lg7+lg2)
分子分母同时除以lg2得:lg7/lg2+3/lg7/lg2+1
即!a·b+3/a·b+1
(ab+3)/(ab+1)

数学对书问题log(2)3=a log(3)7=b 用a和b表示log(14)56 关于数学对数的换底公式推论的问题已知 log(2)(3) = a,log(3(7)=b,用a,b表示log(42)(56)因为log(2)(3)=a,则1/a=log(3)(2),又∵log(3)(7)=b,∴log(42)(56)=log(3)(56)/log(3)(42)=log(3)(7)+3·log(3)(2)/log(3)(7)+log(3)(2)+1=ab+3/ab+b+1 关于数学对数的换底公式推论的问题已知 log(2)(3) = a,log(3(7)=b,用a,b表示log(42)(56)因为log(2)(3)=a,则1/a=log(3)(2),又∵log(3)(7)=b,∴log(42)(56)=log(3)(56)/log(3)(42)=log(3)(7)+3·log(3)(2)/log(3)(7)+log(3)(2)+1=ab+3/ab+b+1 数学问题··关于log1· log(a^k)(M^n)=(n/k)log(a)(M) 的推导过程·2· 2(log(1/2)(x))^2-14log(4)(x)+3 数学 对数计算.log(3)(2)×log(5)(3)= 证明对数运算法则(1)log(a)(MN)=log(a)(M)+log(a)(N);   (2)log(a)(M/N)=log(a)(M)-log(a)(N);(1)log(a)(MN)=log(a)(M)+log(a)(N);   (2)log(a)(M/N)=log(a)(M)-log(a)(N);   (3)log(a)(M^n)=nlog(a)(M) (n∈R) 已知log(14)7=a log(14)5=b 用ab表示log(35)70=log(3)4*log(4)8*log(8)m=log(4)2 求m 已知log(2)^3=a,log(3)^5=b,试用a,b表示log(15)^20 log(x+5)=log(x)+log(2) log(8)+log(x)=log(24) 2log(x)=log(2x)+log(3) log(2)3=a,则log(6)4=( log(2)(a)=log(3)(b)=log(5)(c) 已知log(3)2=a log(5)2=b用ab表示log(30)90 对数函数题 log a - log b = 3 log (c/2) 求 a = ______________ 已知log(2)[log(3)(log(4) x)] = log(3) [log(4) (log(2) y)]=0,求x+y的值 计算题(log)已知log底数5 ^2=a,log底数5 ^3=b求log底数5根号54 的值 log a 2/3 log a(2/3) 若log(3)2=a,用a表示代数式log(2)12=?