已知等腰三角形ABC中,AB=AC,将三角形ABC沿BC方向平移到三角形A'B'C'.且BB'=n乘BC.连AC'交A'B于D,交A'B'于E,(1)如图1,当n=2时,DE/AD= EC'/DE= (2)如图2,当E为DC'中点时,求证n=√2+1(3)当n= 时,点E是A'B'的三等分点
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![已知等腰三角形ABC中,AB=AC,将三角形ABC沿BC方向平移到三角形A'B'C'.且BB'=n乘BC.连AC'交A'B于D,交A'B'于E,(1)如图1,当n=2时,DE/AD= EC'/DE= (2)如图2,当E为DC'中点时,求证n=√2+1(3)当n= 时,点E是A'B'的三等分点](/uploads/image/z/10336191-15-1.jpg?t=%E5%B7%B2%E7%9F%A5%E7%AD%89%E8%85%B0%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2CAB%3DAC%2C%E5%B0%86%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E6%B2%BFBC%E6%96%B9%E5%90%91%E5%B9%B3%E7%A7%BB%E5%88%B0%E4%B8%89%E8%A7%92%E5%BD%A2A%27B%27C%27.%E4%B8%94BB%27%3Dn%E4%B9%98BC.%E8%BF%9EAC%27%E4%BA%A4A%27B%E4%BA%8ED%2C%E4%BA%A4A%27B%27%E4%BA%8EE%2C%281%29%E5%A6%82%E5%9B%BE1%2C%E5%BD%93n%3D2%E6%97%B6%2CDE%2FAD%3D+EC%27%2FDE%3D+%282%29%E5%A6%82%E5%9B%BE2%2C%E5%BD%93E%E4%B8%BADC%27%E4%B8%AD%E7%82%B9%E6%97%B6%2C%E6%B1%82%E8%AF%81n%3D%E2%88%9A2%2B1%283%29%E5%BD%93n%3D+%E6%97%B6%2C%E7%82%B9E%E6%98%AFA%27B%27%E7%9A%84%E4%B8%89%E7%AD%89%E5%88%86%E7%82%B9)
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