这几道数学题这么求啊(1)若cosα=1/7,α∈(0,π/2),则cos(α+π/3)=(2)化简cos(π/3+α)+sin(π/6+α)=(3)求值(1+cos20)/(2sin20)-sin10[(1/tan5)-tan5](4)已知α∈(0,π/2),tanα=1/2,求tan2α和sin(2α+π/3)的值(5)sin163sin223+sin253sin31
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![这几道数学题这么求啊(1)若cosα=1/7,α∈(0,π/2),则cos(α+π/3)=(2)化简cos(π/3+α)+sin(π/6+α)=(3)求值(1+cos20)/(2sin20)-sin10[(1/tan5)-tan5](4)已知α∈(0,π/2),tanα=1/2,求tan2α和sin(2α+π/3)的值(5)sin163sin223+sin253sin31](/uploads/image/z/10352135-47-5.jpg?t=%E8%BF%99%E5%87%A0%E9%81%93%E6%95%B0%E5%AD%A6%E9%A2%98%E8%BF%99%E4%B9%88%E6%B1%82%E5%95%8A%281%29%E8%8B%A5cos%CE%B1%3D1%2F7%2C%CE%B1%E2%88%88%280%2C%CF%80%2F2%29%2C%E5%88%99cos%28%CE%B1%2B%CF%80%2F3%29%3D%282%29%E5%8C%96%E7%AE%80cos%28%CF%80%2F3%2B%CE%B1%29%2Bsin%28%CF%80%2F6%2B%CE%B1%29%3D%283%29%E6%B1%82%E5%80%BC%281%2Bcos20%29%2F%282sin20%29-sin10%5B%281%2Ftan5%29-tan5%5D%284%29%E5%B7%B2%E7%9F%A5%CE%B1%E2%88%88%280%2C%CF%80%2F2%29%2Ctan%CE%B1%3D1%2F2%2C%E6%B1%82tan2%CE%B1%E5%92%8Csin%282%CE%B1%2B%CF%80%2F3%29%E7%9A%84%E5%80%BC%285%29sin163sin223%2Bsin253sin31)
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