已知f(x)=sin(wx+π/3)(w>o),f(6/π)=f(3/π),且f(x)在区间(π/6,π/3)有最小值,无最大值,则w=?
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![已知f(x)=sin(wx+π/3)(w>o),f(6/π)=f(3/π),且f(x)在区间(π/6,π/3)有最小值,无最大值,则w=?](/uploads/image/z/10372235-59-5.jpg?t=%E5%B7%B2%E7%9F%A5f%28x%29%3Dsin%28wx%2B%CF%80%2F3%29%28w%3Eo%29%2Cf%286%2F%CF%80%29%3Df%283%2F%CF%80%29%2C%E4%B8%94f%28x%29%E5%9C%A8%E5%8C%BA%E9%97%B4%28%CF%80%2F6%2C%CF%80%2F3%29%E6%9C%89%E6%9C%80%E5%B0%8F%E5%80%BC%2C%E6%97%A0%E6%9C%80%E5%A4%A7%E5%80%BC%2C%E5%88%99w%3D%3F)
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已知f(x)=sin(wx+π/3)(w>o),f(6/π)=f(3/π),且f(x)在区间(π/6,π/3)有最小值,无最大值,则w=?
已知f(x)=sin(wx+π/3)(w>o),f(6/π)=f(3/π),且f(x)在区间(π/6,π/3)有最小值,无最大值,则w=?
已知f(x)=sin(wx+π/3)(w>o),f(6/π)=f(3/π),且f(x)在区间(π/6,π/3)有最小值,无最大值,则w=?
f(6/π)=f(3/π),所以函数关于4/π对称.且f(x)在区间(π/6,π/3)有最小值 所以X=4/π是对应着最小值.f(x)=sin(wπ/4+π/3)=-1 wπ/4+π/3=-π/2+2Kπ K=1 w>o W=22/3
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