y=sin(-3/2x+π/4)单调递增区间
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y=sin(-3/2x+π/4)单调递增区间
y=sin(-3/2x+π/4)单调递增区间
y=sin(-3/2x+π/4)单调递增区间
化为 y= - sin(3x/2-π/4),
由题,π/2+2kπ≤3x/2-π/4≤3π/2+2kπ,
3π/4+2kπ≤3x/2≤7π/4+2kπ,
π/2+4kπ/3≤x≤7π/6+4kπ/3,k属于Z
递增区间是 [π/2+4kπ/3,7π/6+4kπ/3],
-π/2+2kπ<-3/2x+π/4<π/2+2kπ
解得:-π/6-4kπ/3
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-π/2+2kπ<-3/2x+π/4<π/2+2kπ
解得:-π/6-4kπ/3
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