【数学】三角函数求值,求详解

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【数学】三角函数求值,求详解
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【数学】三角函数求值,求详解
【数学】三角函数求值,求详解

【数学】三角函数求值,求详解
(sin10°+cos70°)/(sin80°+cos20°)
=(sin10°+sin20°)/(cos10°+cos20°)
=2sin15°cos5°/(2cos15°cos5°)
=tan15°
=tan(45º-30º)
=2-√3

很高兴回答您的问题!
(sin10°+cos70°)/(sin80°+cos20°)
=(sin10°+sin20°)/(cos10°+cos20°)
=2sin15°cos5°/(2cos15°cos5°)
=tan15°
=(1-cos30°)/sin30°
=2-√3
希望能帮到您,望采纳!=(sin10°+sin20°)/(cos10...

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很高兴回答您的问题!
(sin10°+cos70°)/(sin80°+cos20°)
=(sin10°+sin20°)/(cos10°+cos20°)
=2sin15°cos5°/(2cos15°cos5°)
=tan15°
=(1-cos30°)/sin30°
=2-√3
希望能帮到您,望采纳!

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(SIN 10+COS 70)/(SIN 80+COS 20)
=(SIN 10+SIN 20)/(COS 10+COS 20)
=(2*SIN 15*COS 5)/(2*COS 15*COS 5)
=(SIN 15)/(COS 15)
=TAN 15
=0.2679491924