lim(2x^-3x+1) x→∞ ^代表平方lim(x的3次方)/2x+1 x→∞lim(x的3次方+5x^)/(x-2)^ 再次拜谢
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lim(2x^-3x+1) x→∞ ^代表平方lim(x的3次方)/2x+1 x→∞lim(x的3次方+5x^)/(x-2)^ 再次拜谢
lim(2x^-3x+1) x→∞ ^代表平方
lim(x的3次方)/2x+1 x→∞
lim(x的3次方+5x^)/(x-2)^ 再次拜谢
lim(2x^-3x+1) x→∞ ^代表平方lim(x的3次方)/2x+1 x→∞lim(x的3次方+5x^)/(x-2)^ 再次拜谢
3个极限都不存在.第一个二次函数显然没有极限.后两个用罗比达法则.
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